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Q.

The eye of a farsighted person has a near point of 90cm. Objects nearer than 90cm cannot be seen clearly. A converging lens is used to correct the vision of a book placed 25cm from the eye. Find the focal length of this lens.

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a

– 34.6cm

b

+ 34.6cm

c

– 40 cm

d

+ 40 cm

answer is D.

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Detailed Solution

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}; u = - 25 cm, v = - 90 cm$

$\frac{1}{f} = \frac{1}{- 90} - \frac{1}{- 25}; f = + 34.6 cm$

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The eye of a farsighted person has a near point of 90cm. Objects nearer than 90cm cannot be seen clearly. A converging lens is used to correct the vision of a book placed 25cm from the eye. Find the focal length of this lens.