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The factor of ${6 x}^{2} - 13 x - 28$ are

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(2 x + 4) (2 x - 7)

(3 x + 4) (2 x - 7)

(4 x + 4) (2 x - 7)

(5 x + 4) (2 x - 7)

answer is B.

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Detailed Solution

There are several options for your x terms:

2 x 3 x

6 x x

You require two integers with a product of

- 28

, or your constants.
This implies that there must be a positive and a negative.
The greater constant must also be negative since the

x -

term, which equals

- 13

, is negative.
Below are your options:

1 - 28, 2 - 14, 4 - 7

Choose the constants that are near together since the

x -

term

= 13 x

is quite small:

4 - 7

Now, we form possible factors:

(6 x + 4) (2 x - 7)

gives the

x -

term

= - 42 x + 8 x = - 34 x

too big

(3 x + 4) (2 x - 7)

gives the

x -

term

= - 21 x + 8 x = - 13 x

correct
As a result, the factors are:

(3 x + 4) (2 x - 7)

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The factor of 6x2 - 13x - 28 are

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The factor of ${6 x}^{2} - 13 x - 28$ are