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The factor of $x^{10} - y^{2}$ are

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(x^{5} + y) (x^{5} - y)

(2 x^{5} + y) (x^{5} - y)

({3 x}^{5} + y) (x^{5} - y)

(6 x^{5} + y) (x^{5} - y)

answer is A.

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Detailed Solution

x^{10} - y^{2}

is the equation that is provided in the query.
The equation for algebra

a^{2} - b^{2} = (a + b) (a - b)

It may be used to factor

x^{10} - y^{2}

Let's suppose that

x^{10}

equals

a^{2}

and

y^{2}

equals

b^{2}

.
So,

a

is thus worth

x^{5}

and

b

is worth

y

.
We are able to write

x^{10} - y^{2} = {(x^{5})}^{2} - {(y)}^{2}

Use of the formula

{(x^{5})}^{2} - {(y)}^{2} = (x^{5} + y) (x^{5} - y)

The form of factorization for

x^{10} - y^{2}

(x^{5} + y) (x^{5} - y)

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