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Q.


The factors of the expression 4 y 2 4y+1  using appropriate identities is:

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a

  (2y – 1) (y – 1)

b

  (2y – 1) (2y – 1)

c

  (2y – 1) (3y – 1)

d

  (2y – 1) (4y – 1) 

answer is B.

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Detailed Solution


Given: 4 y 2 4y+1  
Let us rewrite the given expression as:
= (2y) 2 (2×2y×1)+ 1 2  
Comparing the given expression with a² - 2ab + b², we observe that a = 2y & b = 1.
By Using algebraic identity again, (a – b)² = a² – 2ab + b², we get:
4 y 2 4y+1= (2y1) 2  
=(2y1)(2y1)  
Hence, 4y² – 4y + 1 = (2y – 1) (2y – 1)
Therefore, the correct option is 2.
 
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