The factors of the expression x³ + 13x² + 32x + 20 is:

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The factors of the expression x³ + 13x² + 32x + 20 is:

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(x - 5) (x + 2) (x + 10)

(x - 7) (x + 2) (x + 10)

(x - 5) (x + 5) (x + 10)

(x - 5) (x + 2) (x + 5)

answer is A.

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Detailed Solution

Given: x³ + 13x² + 32x + 20.
First, Let us find the factors of a constant term.
Secondly, let us check out at which factor the given polynomial becomes zero by using the hit and trial method and get one factor of the given polynomial. Then, we shall further divide the polynomial by this factor to get a quotient of the second degree.
Finally, we shall factorize the second-degree polynomial by middle term splitting to get required factors.
Let p(x) = x³ + 13x² + 32x + 20
Here constant term is 20.
Now, let us find the factors of 20:
Factors of 20 are ±1, ±2, ±4, ±5, ±10 and ±20.
By using hit and trial method substitute x = - 1in p(x) we get: