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The far point of a shortsighted woman is 75cm from the eye. What focal length lens should the woman use in order to focus on a very distant object ( $U = \infty$ ) ? Also find power of the lens.

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–3.4D

–1.9D

–1.33D

–2.33D

answer is A.

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Detailed Solution

$\frac{1}{f} = \frac{1}{V} - \frac{1}{u}; u = \infty, v = - 75 cm$

$\frac{1}{f} = \frac{- 1}{75}, P = \frac{- 100}{75} = - 1.33 D$

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