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The far point of myopic person is $80 cm$ in front of the eye. Power of the lens required to correct the problem [[1]] $D$ .

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Detailed Solution

The far point of myopic person is

80 cm

in front of the eye. Power of the lens required to correct the problem is

- 1.25 D

.
The concave lens is required to correct myopia.
Given:

Object distance, u = \infty

Image distance, v = - 80 cm

Using lens formula,

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

\Rightarrow \frac{1}{f} = - \frac{1}{80} - \frac{1}{\infty}

\Rightarrow f = - 80 cm

∴ f = - 0.8 m

Power P = \frac{1}{f}

\Rightarrow P = - \frac{1}{0.8}

∴ P = - 1.25 D

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