The favourable conditions for a spontaneous reaction are

•  The free energy charge $∆\mathrm{G}$ is given by, $∆\mathrm{G}=∆\mathrm{H}-\mathrm{T}∆\mathrm{S}$
• The reaction is spontaneous if $∆\mathrm{G}<0$.

$\Rightarrow ∆\mathrm{H}-\mathrm{T}∆\mathrm{S}<0$

$\Rightarrow \mathrm{T}∆\mathrm{S}>\Delta \mathrm{H},∆\mathrm{H}=+\mathrm{ve},∆\mathrm{S}=+\mathrm{ve}$

Hence the correct answer is (A) $\mathrm{T}\Delta \mathrm{S}>\Delta \mathrm{H},\Delta \mathrm{H}=+\mathrm{ve},\Delta \mathrm{S}=+\mathrm{ve}$