The fig. (1)shows four progressive waves A, B, C and D

with their phases expressed with respect to the wave A. It can be concluded from the figure that

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the wave C is ahead by a phase angle of $π$ / 2 and the wave B lags behind by a phase angle of $π$ / 2

the wave C is ahead by a phase angle of $π$ and the wave B lags behind by a phase angle of $π$

the wave C lags behind by a phase angle of $π$ / 2 and the wave B is ahead by a phase angle of $π$ / 2

the wave C lags behind by a phase angle of $π$ and the wave B is ahead by a phase angle of $π$

answer is B.

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Detailed Solution

It is clear from figure that the wave A attains its mean position T/4 time earlier than C i.e., C lags behind A by phase angle $π$ /2. Further, B attains the mean position T/4 time earlier than A, i.e., B is ahead by a phase angle of $\frac{π}{2}$ .

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