Q.

The figure below is the plot of potential energy versus internuclear distance (๐‘‘) of H2 molecule in the electronic ground state. What is the value of the net potential energy ๐ธ0 (as indicated in the figure) in kJ molโˆ’1, for ๐‘‘=๐‘‘0 at which the electron-electron repulsion and the nucleus-nucleus repulsion energies are absent? As reference, the potential energy of H atom is taken as zero when its electron and the nucleus are infinitely far apart. 

Use Avogadro constant as 6.023 ร— 1023 molโˆ’1.

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Detailed Solution

At d = d0, nucleus-nucleus & electron-electron repulsion is absent.
Hence potential energy will be calculated for 2 H atoms. (P.E. due to attraction of proton & electron)
 P.E. =โˆ’Kq1q2r(Bohar radius)=9ร—1091.6ร—10โˆ’1920.529ร—10โˆ’10=โˆ’4.355ร—10โˆ’21kJ

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For 1 mol = โ€“4.355 ร— 10โ€“21 ร— 6.023 ร— 1023 = โ€“2623.249 kJ/mol
For 2 H atoms = โ€“5246.49 kJ/mol 

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