The figure shows a graph of the current in a discharging circuit of a capacitor through a resistor of resistance $10 Ω$

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The initial potential difference across the capacitor is 100V

The capacitance of the capacitor is $\frac{1}{10 \ln 2} F$

The total heat produced in the circuit will be $\frac{500}{\ln 2} J$

All of the above

answer is D.

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Detailed Solution

$\begin{array}{l} V_{0} = i_{0} R = 100 V \\ I = I_{0} e^{\frac{- t}{CR}} \Rightarrow C = \frac{1}{10 \ln 2} F \\ H = \int dH = \int_{0}^{\infty} I^{2} Rdt = \frac{500}{\ln 2} J \end{array}$

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