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Q.

The figure shows a metallic plate of uniform thickness and density. The value of l in terms of L so that the centre of mass of the system lies at the interface of the triangular and rectangular portion is 

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a

l=L2

b

l=L3

c

l=L3

d

l=2L3

answer is C.

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Detailed Solution

 If the interface is taken as the origin then l2bl-L312bL=0

Center of mass of the triangle is L3from the base.

m1x1+m2x2m1+m2=0

Here mass is proportional to area I2=L23

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