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Q.

The figure shows a meter-bridge circuit where $X = 12 Ω$ and $R = 18 Ω$ . The jockey J is at the null point. If R is made $8 Ω$ through what distance will the jockey J have to be moved to obtain null point again?

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a

10 cm

b

20 cm

c

30 cm

d

40 cm

answer is B.

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Detailed Solution

$\frac{AJ}{100 - AJ} = \frac{X}{R} = \frac{12}{18} \Rightarrow AJ = 40 cm$

After changing R:

$\begin{array}{l} \frac{{AJ}^{'}}{100 - {AJ}^{'}} = \frac{12}{8} \Rightarrow {AJ}^{'} = 60 cm \\ Shifting : {AJ}^{'} = 20 cm \end{array}$

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The figure shows a meter-bridge circuit where X=12 Ω and R=18 Ω. The jockey J is at the null point. If R is made 8 Ω through what distance will the jockey J have to be moved to obtain null point again?