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Q.

The figure shows a region of length ‘l’ with a uniform magnetic filed of 0.3T in it and a proton entering the region with velocity 4 × 105 ms-1 making an angle 600 with the field. If the proton completes 10 revolution by the time it cross the region shown, ‘l’ is close to (mass of proton = 1.67 × 10-27 kg, charge on the proton = 1.6 × 10-19C)

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a

0.11 m

b

0.44 m

c

0.22 m

d

0.88 m

answer is A.

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Detailed Solution

 

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l=10pitch=102πMqBVcosθ=10×2π×1.67×1027×4×105cos6001.6×1019×0.3

l=0.44m

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