The figure shows a transparent sphere of radius R and refractive index $μ$ . An object O is placed at a distance x from the pole of the first surface so that a real image is formed at the pole of the exactly opposite surface.

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If $x = \infty$ , then the value of $μ$ is 3

If $x = \infty$ , then the value of $μ$ is 2

If x = 2R, then the value of $μ$ is 3

If x = 2R, then the value of $μ$ is 2

answer is A, B.

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Detailed Solution

$\frac{μ}{2 R} - \frac{1}{- x} = \frac{μ - 1}{R} X = \frac{2 R}{μ - 2}$

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