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Q.

The figure shows collision between two masses M and 3M on a smooth horizontal surface Before the collision the mass M has a velocity V1 in the y-direction. The mass 3 M has a velocity (5/12) V0 making an angle θ to the x-axis as shown. After the collision the mass 3 M comes to rest and the mass M moves along the x-axis with the velocity V1'(seefig(2)). Then, neglecting gravity, (Given sinθ=3/5) choose the correct options.

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a

the speed V1  of mass M before collision is  V04

b

the speed  V1' of mass M after collision is  V02.

c

the speed V1'  of mass M after collision is  V0.

d

the speed  V1 of mass M before collision is   34V0

answer is A, D.

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Detailed Solution

Final momentum in y-axis is zero.
So  MV1=512V0sinθ 3 M
  V1=34V0
 Along  xaxis Initial momentum = final momentum    512V0sinθ3M=MV1'
  
V1'=V0

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