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The figure shows electronic wave function for a hydrogen atom.

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The quantum number of this state is 6

On de-excitation it emits at least one line in infrared region of spectrum.

The wavelength of this electron is $6 π r_{0}$ . ( $r_{0}$ is radius of ground state)

can go to ground state by emitting 3 different photons

answer is B, C.

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Detailed Solution

Number of waves in the given diagram is 3. Hence n = 3
$λ = \frac{2 π r}{3} = \frac{2 π r_{0} 3^{2}}{3} = 6 π r_{0}$
Possible transmissions in de excitation a. e
$3 \to 2, 3 \to 1, 2 \to 1$

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