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Q.

The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If $t 1$ is the time for the planet to move from C to D and $t 2$ is the time to move from A to B then:-

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a

t 1 = 2 t 2

b

t 1 = t 2

c

t 1 = 4 t 2

d

t 1 < t 2

answer is D.

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Detailed Solution

$A 1 t 1 = A 2 t 2$

$\Rightarrow \frac{2 A}{t_{1}} = \frac{A}{t_{2}}$

$\Rightarrow t_{1} = 2 t_{2}$

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