The figure shows part of certain circuit 
 

(i) Current flow through resistance $5\mathrm{\Omega }$ is 11amp Power dissipated = ${\mathrm{i}}^2\mathrm{R}=121\times 5=605$W

ii) ${\mathrm{V}}_{\mathrm{B}}+8\mathrm{V}+3\mathrm{V}+12\mathrm{V}-12\mathrm{V}-5\mathrm{V}={\mathrm{V}}_{\mathrm{C}}$

$\Rightarrow {\mathrm{V}}_{\mathrm{C}}-{\mathrm{V}}_{\mathrm{B}}=6\mathrm{V}$

iii) Both batteries are being charged

iv) P=i²R=16x6=96W