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The figure shows stopping potential $V_{0}$ and frequency $ν$ for two different metallic surfaces $A a n d B .$ The work function of $A,$ as compared to that of $B$ is _____.

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less

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answer is A.

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Detailed Solution

The value of threshold frequency $ν_{0}$ for $A$ is less than that for $B .$

Therefore, work function of A is less than work function of B. i.e. $ϕ_{A} < ϕ_{B}$ .

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