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The Figure shows the variation of force and displacement. The value of work done at the end of the displacement $30 m$ is.

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50 J

100 J

- 50 J

- 100 J

answer is A.

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Detailed Solution

The value of work done at the end of the displacement

30 m

50 J

.
The area under the force and displacement graphs, gives work done.
The area under the graph is as follows,

W = (\frac{1}{2} \times 20 \times 10) - (\frac{1}{2} \times 10 \times 10)

⇨

W = (100) - (50)

⇨

W = 50 J

The work done at the end of

30 m

displacement is

50 J

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