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Q.

The figure shows the variation of photo-current (i) and anode potential (V) for a photo sensitive surface for three different radiations. Let Ia, Ib and Ic be the intensities and fa, fb and fc be the frequencies for the curves A, B and C respectively, then

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a

IaIc, fbfc

b

IaIb, fb=fc

c

Ib=Ic, fafb

d

Ia=Ic, fb=fc

answer is C.

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Detailed Solution

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Saturation current for B and C is same, so, Intensity of photons in B and C is same.

Ia=Ic

The Saturation current for A is lesser than that of B and C, so, Ia<Ib=Ic

Stopping potential for A and B is same, so, frequency of A and B is same.

fa=fb

The magnitude of stopping potential for C is larger than that of A and B, so, fc>fa=fb.

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