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The figure shows the velocity $(v)$ of a particle plotted against time $(t)$
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The particle changes its direction of motion at some point

The acceleration of the particle remains constant

The displacement of the particle is zero

The initial and final speeds of the particle are the same

answer is A, B, C, D.

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Detailed Solution

For $t < T, v = - v e$
For $t > T, v = + v e$
At $t = T, v = 0$
$∴$ Particle changes direction of velocity at $t = T$
$s =$ Net area of $v - t$ graph $= 0$
$a =$ Slope of $v - t$ graph $=$ constant

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