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Q.

The figure shows the P-V plot of an ideal gas taken through a cycle ABCDA. The part ABC is a semi-circle and CDA is half of an ellipse. Then 

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a

The process during the path AB is isothermal 

b

Heat flows out of the gas during then path BCD

c

Work done during the path ABC is zero

d

Positive work is done by the gas in the cycle ABCDA

answer is B, D.

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Detailed Solution

Temperature at B > temperature at D

U is negative (for B CD)

Also W is negative (for B CD

Tracing is clockwise on PV diagram.

Total W is positive. (2) and (4) are Correct

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