The figure shows two slits $S_{1} a n d S_{2}$ in a horizontally fixed place. Here $d = 1 m m, D = 1 m$ Take origin at O, (midpoint of $S_{1} a n d S_{2}$ ) and XY plane as shown in the figure. The screen is released from rest under gravity vertically downwards from the initial position as shown. (take $g = 10 m s^{- 2}$ ) The velocity of central maxima at $t = 5 \sec$ is____ $m s^{- 1}$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 50.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$(D - y) = - \frac{1}{2} g t^{2} y - D = \frac{1}{2} g t^{2} y = D + \frac{1}{2} g t^{2} \Rightarrow \frac{d y}{d t} = \frac{1}{2} g 2 t = g t = 50 m s^{- 1}$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!