The figure shows two wires tied to a sphere which revolves in a horizontal circle at constant speed. The mass of the sphere is (3+1) kg. At this particular speed the tension is same in both the wires. The value of tension (in N) is T0. T010 is equal to: (Assume g=10 m/s2 )

Tsin60°+Tsin30°=mgT=mgsin60°+sin30°

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The figure shows two wires tied to a sphere which revolves in a horizontal circle at constant speed. The mass of the sphere is $(\sqrt{3} + 1)$ kg. At this particular speed the tension is same in both the wires. The value of tension (in N) is $T_{0} . \frac{T_{0}}{10}$ is equal to: (Assume $g = 10 m / s^{2}$ )

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answer is 2.

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$\begin{array}{l} T \sin 60 ° + T \sin 30^{°} = m g \\ T = \frac{m g}{\sin 60 ° + \sin 30 °} \end{array}$

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