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The figure shows velocity-time graph of a particle moving along a straight line. Identify the correct statement.

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The particle starts from the origin

The particle crosses it initial position at $t = 2 s$

The average speed of the particle in the time interval, $0 \leq t \leq 2 s$ is zero

All of the above

answer is B.

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Detailed Solution

$s = D i s p l a c e m e n t =$ area of $v - t$ graph

At t=2 s, net area =0

displacement=0,but distance travelled is not zero

$∴ s = 0$

and the particle crosses its initial position.

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