The final major product of the following reaction is

 

$-NHCOC{H}_3$ is moderately activating wins over weak activating $-{\mathrm{CH}}_3$and due to bulky nature of$-NHCOC{H}_3$attack happens para to $-NHCOC{H}_3$

or

The reaction with acetic anhydride leads to the formation of N-Acetyl derivative, Now the para position is free rather than ortho.