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Q.

The first ionization energy of caesium is 6.24 x 10- 19 J/atom. What is the minimum frequency of light that is required to ionize a caesium atom?

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a

1.06×10−15s−1

b

4.13×1014s−1

c

9.42×1014s−1

d

1.60×1018s−1

answer is C.

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Detailed Solution

The minimum frequency of light that is required to ionize a caesium atom;

6.625×10−34×v=6.24×10−19⇒                       v=9.42×1014s−1

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