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The first IP of lithium is 5.41eV and electron affinity of Cl is -3.61eV. Calculate ΔH in KJmol^–1 for the reaction Li_(g) + Cl_(g) → Li_(g)⁺ + Cl^–_(g)

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-173.7

173.7

17.3

1.73

answer is A.

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Detailed Solution

IP₁ of Li is 5.41ev and EA of Cl is 3.6 ev
Li_(g) → Li⁺_(g) ΔH=+5.41ev
Cl_(g) → Cl^-_(g) ΔH=-3.6ev
ΔH = 1.8(96.45)
= +173.7 KJ
Li(g) + Cl_(g) → Li⁺(g) + Cl^-_(g)ΔH=+1.8ev

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