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Q.

The first IP of lithium is 5.41eV and electron affinity of Cl is -3.61eV. Calculate ΔH in KJmol–1 for the reaction Li(g) + Cl(g) → Li(g)+ + Cl–(g)

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a

-173.7

b

173.7

c

17.3

d

1.73

answer is A.

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Detailed Solution

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IP1 of Li is 5.41ev and EA of Cl is 3.6 ev
Li(g) → Li+(g) ΔH=+5.41ev
Cl(g) → Cl-(g) ΔH=-3.6ev
ΔH = 1.8(96.45)
     = +173.7 KJ
Li(g) + Cl(g)  → Li+(g) + Cl-(g)  ΔH=+1.8ev

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