The first order diffraction of x-rays from a certain set of crystal planes occurs at an angle of 11.8∘ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is(sin11.8°=0.2, sin 5.9°=0.103)

Given: n=1, d=0.281×10-9 m,θ=11.82d sinθ=nλ∴λ=2×0.281×10-9×sin11.81λ=2×0.281×10-9×0.2044=0.1149 nmTherefore, the correct option is (A).

The first order diffraction of x-rays from a certain set of crystal planes occurs at an angle of 11.8∘ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is(sin11.8°=0.2, sin 5.9°=0.103)

Given: n=1, d=0.281×10-9 m,θ=11.82d sinθ=nλ∴λ=2×0.281×10-9×sin11.81λ=2×0.281×10-9×0.2044=0.1149 nmTherefore, the correct option is (A).

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The first order diffraction of x-rays from a certain set of crystal planes occurs at an angle of $11 . 8^{\circ}$ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is
( $\sin 11.8 ° = 0.2, \sin 5.9 ° = 0.103$ )

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0.0578 nm

0.578 nm

0.1149 nm

1.124 nm

answer is A.

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Detailed Solution

Given: $n = 1, d = 0.281 \times 10^{- 9} m, θ = 11.8$

$2 d sinθ = nλ$

$∴ λ = \frac{2 \times 0.281 \times 10^{- 9} \times \sin 11.8}{1}$

$λ = 2 \times 0.281 \times 10^{- 9} \times 0.2044 = 0.1149 nm$

Therefore, the correct option is (A).

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The first order diffraction of x-rays from a certain set of crystal planes occurs at an angle of 11.8∘ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is(sin11.8°=0.2, sin 5.9°=0.103)

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The first order diffraction of x-rays from a certain set of crystal planes occurs at an angle of $11 . 8^{\circ}$ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is
( $\sin 11.8 ° = 0.2, \sin 5.9 ° = 0.103$ )