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Q.

The first order reaction is carried out starting with 10 mol L-1 of the reactant. It is 40 % complete in one hour. If the reaction is carried out with an initial concentration of 5 mol L-1 the percentage of the reaction that is completed in one hour will be

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a

40%

b

80 %

c

20%

d

60%

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Kt=2.303 log initialfinal

K=2.3031log106

Now, Kt=2.303loginitialfinal

2.303log106×1=2.303log5final

log106=log5final

final=6×510=3

% of completion=5-35×100=40%

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