The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm. The length of the open organ pipe is ___

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The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm. The length of the open organ pipe is ____ cm

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answer is 80.

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Detailed Solution

L_cp = 20cm, L_op=?

1^st overtone of OP = Fundamental frequency of closed pipe

$2 (\frac{V}{2 l_{o p}}) = \frac{V}{4 l_{c p}}$

$l_{o p} = 4 l_{c p}$

$= 4 \times 20 = 80 c m$

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