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The first,second and third ionization enthalpies of a metal (M) are respectively 417,3069 and 4059 kJ/mole. The correct formulae of the compound formed by the metal among the following is

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M₃(CO₂)₂

M₂N₃

M₂O₃

MOH

answer is C.

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Detailed Solution

The large gap between first and second ionization enthalpies indicates that the valency electronic configuration of metal is ns¹

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