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The five successive ionization enthalpies of an element are 800, 2427, 3658, 25024 and 32824 $k J m o l^{- 1} .$ The number of valence electrons in the element is:

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answer is C.

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Detailed Solution

As difference in $3^{r d}$ and $4^{t h}$ ionization energies is high, so atom contains 3 valence electrons

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