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The flocculation value of $H C l$ for arsenic sulphide sol is $30 m m o l L^{- 1}$ . If $H_{2} S O_{4}$ is used for the flocculation of the same sol, the mass (in g) of $H_{2} S O_{4}$ required for 1L of the sol is

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answer is 1.47.

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Detailed Solution

1 mole of $H C l \equiv 0.5 m o l e o f H_{2} S O_{4}$
$∴ 30 m m o l o f H C l = 15 m m o l o f H_{2} S O_{4}$
Mass of $H_{2} S O_{4} = n \times G M W$
$= 15 \times 10^{- 3} \times 98 = 1.47 g$

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