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The floor of a rectangular hall has a perimeter $250$ m. If the cost of painting the four walls at the rate of Rs. $10$ per $m^{2}$ is Rs. $15000$ , find the height (in cm) of the hall.

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400

500

600

700

answer is C.

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Detailed Solution

Here, Area of the four walls

=

2 lh + 2 bh

= 2 h (l + b)

Perimeter of floor of wall

= 2 l + 2 b

= 2 (l + b)

= 250 m

∴

Area of

4

walls

= 2 (l + b) h

= 250 h m^{2}

Now
We calculate cost of painting per

m^{2}

area = Rs.

10

Hence, the cost of painting

250 h m^{2}

area = Rs

(250 h \times 10)

= Rs . 2500 h

Painting cosy of walls = Rs.

15000

\Rightarrow 2500 h = 15000

\Rightarrow h = \frac{15000}{2500}

\Rightarrow h = 6 m

The height of the hall is

600

cm.

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