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The flux linked with a coil at any instant of time t is given by $φ = 10 t^{2} - 50 t + 25$ . The induced emf at t = 3s is

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10 V

–190 V

– 10 V

190 V

answer is B.

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Detailed Solution

$φ = 10 t^{2} - 50 t + 25$

$e = - \frac{d φ}{d t} = - \frac{d}{d t} (10 t^{2} - 50 t + 25)$

$e = - 20 t + 50$

$A t t = 3 \sec,$

$e = - 10 V$

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