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The focal length of a convex lens of refractive index 1.5 is f when it is placed in air. When it is immersed in a liquid it behaves as a converging lens and its focal length becomes xf (x > 1). The refractive index of the liquid is

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> 3/2

< 3/2

= 3/2

< 3/2 and > 1

answer is B.

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Detailed Solution

$\frac{f^{l}}{f} = \frac{μ_{g} - 1}{(\frac{μ_{g}}{μ_{l}} - 1)}$

$f^{l} = xf and x > 1$

$∴ μ_{l} < μ_{g} \Rightarrow μ_{l} < \frac{3}{2}$

$μ_{l} is absolute refractive index always > 1$

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