The focal length of a mirror is given by 2f=1V−1U In finding the values of U and V the errors are equal and equal to P then relative error in f

2f=1V−1U −2f2Δf=−1r2ΔV+1U2ΔU 2fΔff=1V2P−1U2P Δff=P(1V+1U)

The focal length of a mirror is given by 2f=1V−1U In finding the values of U and V the errors are equal and equal to P then relative error in f

2f=1V−1U −2f2Δf=−1r2ΔV+1U2ΔU 2fΔff=1V2P−1U2P Δff=P(1V+1U)

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The focal length of a mirror is given by $\frac{2}{f} = \frac{1}{V} - \frac{1}{U}$ In finding the values of U and V the errors are equal and equal to P then relative error in f

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$\frac{P}{2} (\frac{1}{U} + \frac{1}{V})$

$P (\frac{1}{U} + \frac{1}{V})$

$\frac{P}{2} (\frac{1}{U} - \frac{1}{V})$

$P (\frac{1}{U} - \frac{1}{V})$

answer is B.

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$\frac{2}{f} = \frac{1}{V} - \frac{1}{U} - \frac{2}{f^{2}} Δ f = - \frac{1}{r^{2}} Δ V + \frac{1}{U^{2}} Δ U \frac{2}{f} \frac{Δ f}{f} = \frac{1}{V^{2}} P - \frac{1}{U^{2}} P \frac{Δ f}{f} = P (\frac{1}{V} + \frac{1}{U})$

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The focal length of a mirror is given by 2f=1V−1U In finding the values of U and V the errors are equal and equal to P then relative error in f

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The focal length of a mirror is given by $\frac{2}{f} = \frac{1}{V} - \frac{1}{U}$ In finding the values of U and V the errors are equal and equal to P then relative error in f