The focal length of the objective and eyepiece of a compound micro scope are 2.0 cm and 3.0 cm respectively the distance between the objective and eyepiece is 15 cm. The final image formed by the eyepiece is at infinity. The two lenses are thin, the distance (in cm) of the object and the image produced by the objective, measured from the objective lens are respectively

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2.0 and 12.0

2.4 and 15.0

2.0 and 3.0

2.4 and 12.0

answer is A.

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Detailed Solution

According to the question the final image is formed at infinity.
The object for eyepiece (image formed by objective lens) should be at a distance of f=3cm from it.

Hence distance of the image formed by the objective lens from the objective lens is 15-3=12cm

For objective $\frac{1}{v_{0}} - \frac{1}{u_{0}} = \frac{1}{f_{0}}$
$\begin{array}{l} f_{0} + u_{e} = L \\ \frac{1}{v_{e}} - \frac{1}{u_{e}} = \frac{1}{f_{e}} \end{array}$