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The focal lengths of the objective and the eye – piece of a compound microscope are 2.0 cm and 3.0 cm respectively. The distance between the objective and the eyepiece is 15.0 cm. The final image formed by the eyepiece is at infinity. The two lenses are thin. The distances in centimeters of the objeect and image produced by the objective measured from the objective respectively.

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An Intiative by Sri Chaitanya

2.4 and 12

2.4 and 15

2.3 and 3

2 and 12

answer is A.

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Detailed Solution

L = V₀ + u_e ; u_e = f_e = 3cm
$\begin{array}{l} V_{0} = 15 - 3 = 12 cm \\ u_{0} = \frac{V_{0} f_{0}}{V_{0} - f_{0}} = \frac{12 \times 2}{10} = 2 .4 cm \end{array}$

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