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Q.

The focus of a parabola is (1,2) and the point of intersection  of the directrix and axis is (2,3) . Then the equation of the parabola is

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a

(x−1)2+(y−2)2=14(x+y−5)2

b

(x−1)2+(y−2)2=12(x+y−5)2

c

(x−1)2+(y−2)2=125(x+y−5)2

d

(x−1)2+(y−2)2=15(x+y−5)2

answer is B.

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Detailed Solution

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S(1,2),Z(2,3); Directrix y−3=−1(x−2),Now use SP2=PM2

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The focus of a parabola is (1,2) and the point of intersection  of the directrix and axis is (2,3) . Then the equation of the parabola is