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Q.

The following are the statements regarding polarising power of IIA group cations

i) Be always forms covalent compounds due to high polarising power of Be+2 ions

ii) Be always form covalent compounds due to low polarising power of Be+2 ions

iii) Polarising power of IIA cations decreases from Be+2 ion to Ba+2 ion

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a

i, ii and iii

b

i and ii

c

iii and i

d

ii and iii

answer is C.

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Detailed Solution

BeCl2 > MgCl2 > CaCl2 > SrCl2 > BaCl2 : percentage covalent character
 

\large \xrightarrow{{B{e^{ + 2}} > {\text{ }}M{g^{ + 2}} > {\text{ }}C{a^{ + 2}} > {\text{ }}S{r^{ + 2}} > {\text{ }}B{a^{ + 2}}}}:\;Polarising\;power\;of\;cation


As the size of cation decreases, effective nuclear charge decreases, and hence polarising power of cation decreases,
Distortion of electron cloud in anion by cation decreases, hence sharing property of electron pair in M-Cl bond decreases
 

\large Polarising\;power\;of\;cation\; \propto \;\frac{1}{{Size\;of\;cation}}\; \propto \;\% \;\operatorname{cov} alent\;charater


Therefore statement-I and Statement - III are correct

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