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The following are the statements regarding polarizing power of IIA group cations
i) Be always forms covalent compounds due to high polarizing power of Be⁺² ions
ii) Be always form covalent compounds due to low polarizing power of Be⁺² ions
iii) Polarizing power of IIA cations decreases from Be⁺² ion to Ba⁺² ion
The correct combination is

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i and ii

ii and iii

iii and i

i, ii and iii

answer is C.

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Detailed Solution

BeCl₂ > MgCl₂ > CaCl₂ > SrCl₂ > BaCl₂ : percentage covalent character

\large \xrightarrow{{B{e^{ + 2}} > {\text{ }}M{g^{ + 2}} > {\text{ }}C{a^{ + 2}} > {\text{ }}S{r^{ + 2}} > {\text{ }}B{a^{ + 2}}}}:\;Polarising\;power\;of\;cation

As the size of cation decreases, effective nuclear charge decreases, and hence polarising power of cation decreases,
Distortion of electron cloud in anion by cation decreases, hence sharing property of electron pair in M-Cl bond decreases

\large Polarising\;power\;of\;cation\; \propto \;\frac{1}{{Size\;of\;cation}}\; \propto \;\% \;\operatorname{cov} alent\;charater

Therefore statement-I and Statement - III are correct

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