The following are the statements regarding polarizing power of IIA group cations
i) Be always forms covalent compounds due to high polarizing power of Be⁺² ions
ii) Be always form covalent compounds due to low polarizing power of Be⁺² ions
iii) Polarizing power of IIA cations decreases from Be⁺² ion to Ba⁺² ion
The correct combination is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

i and ii

iii and i

i, ii and iii

ii and iii

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

BeCl₂ > MgCl₂ > CaCl₂ > SrCl₂ > BaCl₂ : percentage covalent character

\large \xrightarrow{{B{e^{ + 2}} > {\text{ }}M{g^{ + 2}} > {\text{ }}C{a^{ + 2}} > {\text{ }}S{r^{ + 2}} > {\text{ }}B{a^{ + 2}}}}:\;Polarising\;power\;of\;cation

As the size of cation decreases, effective nuclear charge decreases, and hence polarising power of cation decreases,
Distortion of electron cloud in anion by cation decreases, hence sharing property of electron pair in M-Cl bond decreases

\large Polarising\;power\;of\;cation\; \propto \;\frac{1}{{Size\;of\;cation}}\; \propto \;\% \;\operatorname{cov} alent\;charater

Therefore statement-I and Statement - III are correct

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th