The following data set has a mean 14.7 and variance of 10.01.
18, 11, 12, a, 16, 11, 19, 14, b, 13, then possible value of 2a + b can be
 

$$\begin{gathered} \overline{x}=\frac{18+ 11+ 12+a+ 16+ 11+ 19+ 14+ b+ 13}{10} \\ 14.7=\frac{114+a+b}{10}\Rightarrow a+b=33 \end{gathered}$$
$$\begin{gathered} variance=\frac{{18}^2+{11}^2+{12}^2+a^2+{16}^2+{11}^2+{19}^2+{14}^2+b^2+{13}^2}{10}-{(14.7)}^2 \\ 10.01=\frac{1692+a^2+b^2}{10}-216.09 \\ \Rightarrow 1692+a^2+b^2=2261 \\ \Rightarrow a^2+b^2=569 \\ a=20, b=13 or a=13, b=20 \\ 2a+b=46 \end{gathered}$$