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The following diagram indicates the energy levels of a certain atom when the system moves from 4E level to E level. Then a photon of wavelength $λ_{1}$ is emitted. The wavelength of photon produced during transition from $\frac{7}{3} E$ to E is $λ_{2}$ . Then $\frac{λ_{1}}{λ_{2}}$ is___

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$\frac{9}{4}$

$\frac{2}{3}$

$\frac{4}{9}$

$\frac{3}{2}$

answer is B.

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Detailed Solution

$4 E - E = \frac{h C}{λ_{1}} & \frac{7 E}{3} - E = \frac{h C}{λ_{2}}$

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