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The following diagram represents the equilibrium state for the reaction:
$A_{2} (g) + 2 B (g) ⇌_{}^{} 2 A B (g)$
molar concentration is defined as the number of particle units per litre

To what final volume(in litres) the piston must be shifted from 1 litre so that the new equilibrium contains only one particle unit of AB in the container

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answer is 48.

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Detailed Solution

$K_{c} = \frac{{[A B]}^{2}}{[A_{2}] {[B]}^{2}} = \frac{9}{3 \times 4} = 0.75 L m o l^{- 1}$

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