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Q.

The following distribution's mode is

Class Interval:1-56-1011-1516-2021-25
Frequency:471086

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a

14.5

b

16.5

c

10.5

d

13.5

answer is D.

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Detailed Solution

We begin by determining whether the given data in the frequency table is continuous or not.

If the data is continuous, we proceed to the mode; otherwise, we add the correction factor to the lower and upper boundaries of the class intervals to make them continuous.

The modal group is then determined by finding the class with the greatest number of frequency

Use the formula, me=L+fm-fm-1fm-fm-1+fm-fm+1×I

 Modal group =11-15, since it has the highest frequency i.e 10 .

 Estimated Mode M=L+fm-fm-1fm-fm-1+fm-fm+1×w

Lower class boundary of modal group L=10.5

Frequency of group before the modal group fm-1=7

Frequency of Modal group fm=10

Frequency of group after the modal group fm+1=8

Group width w=5

M=10.5+10-710-7+10-8×5

=10.5+35×5

=13.5 

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