The following equilibria are given $N_{2} + {3 H}_{2} ⇌ 2 {NH}_{3}; K_{c} = K_{1}; N_{2} + O_{2} ⇌ 2 NO; K_{c} = K_{2}; H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O_{2}; K_{c} = K_{3}$ The equilibrium constant of the reaction. $2 {NH}_{3} + \frac{5}{2} O_{2} ⇌ 2 NO + 3 H_{2} O$ on the term of $K_{1}, K_{2}$ and $K_{3}$ is

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$K_{1} K_{2} K_{3}$

$K_{1} K_{2} / K_{3}$

$K_{1} {K_{3}}^{2} K_{3}$

$K_{1} {K_{3}}^{3} / K_{1}$

answer is D.

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Detailed Solution

$2 {NH}_{3} + \frac{5}{2} O_{2} ⇌ 2 NO + 3 H_{2} O$

Equation adding $b + 3 c - a$

$K = \frac{K_{2} \times {K_{3}}^{3}}{K_{1}}$

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